Sunday, August 2, 2009

Find quadratic function y=ax^2+c using points....???

1).(0,2) and (3,5)


2.) (2,5/2) and (0, -1/2)

Find quadratic function y=ax^2+c using points....???
1) For x=0 and y=2 ==%26gt; 2=a.0+c


2=c


For x=3 and y=5 ==%26gt; 5=a.3+c


5=3a+2


3=3a


1=a


So our equation is y=ax^2+c


y= x^2+2


2) For x=0 and y=-1/2 ==%26gt; -1/2=a.0+c


-1/2=c


For x=2 and y=5/2 ==%26gt; 5/2=a.2+c


5/2=2a-1/2


2=2a


1=a


Our equation is y=ax^2+c


y= x^2-1/2

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