1).(0,2) and (3,5)
2.) (2,5/2) and (0, -1/2)
Find quadratic function y=ax^2+c using points....???
1) For x=0 and y=2 ==%26gt; 2=a.0+c
2=c
For x=3 and y=5 ==%26gt; 5=a.3+c
5=3a+2
3=3a
1=a
So our equation is y=ax^2+c
y= x^2+2
2) For x=0 and y=-1/2 ==%26gt; -1/2=a.0+c
-1/2=c
For x=2 and y=5/2 ==%26gt; 5/2=a.2+c
5/2=2a-1/2
2=2a
1=a
Our equation is y=ax^2+c
y= x^2-1/2
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