Display this design using C++..?

how do i display an inverted pyramid of asterisks ?...using 'for' loops, 'if' conditions..etc...


as in to display a straight pyramid the code would be:


#include%26lt;iostream.h%26gt;


#include%26lt;conio.h%26gt;


void main()


{clrscr();


int i,j,k,l=1,num;


cout%26lt;%26lt;"Enter the no:"%26lt;%26lt;endl;


cin%26gt;%26gt;num;


for(k=num;k%26gt;=1;k--)


{ for(i=k;i%26gt;=1;i--)


cout%26lt;%26lt;" ";


if(l%26lt;num)


{ for(j=1;j%26lt;=l;j++)


cout%26lt;%26lt;"*"%26lt;%26lt;" ";


}


l++;


cout%26lt;%26lt;endl;


}

















getch();





}

Display this design using C++..?
//


// Display a pyramid of asterisks, upright or inverted:


// usage: ./pyramid %26lt;n%26gt;


// if n %26lt; 0, the pyramid is inverted.


//


#include %26lt;iostream%26gt;


#include %26lt;iomanip%26gt;


#include %26lt;cstdio%26gt;





using namespace std;





int main(int argc, char *argv[])


{


int n, startX, endX, increment;


const string star("*");





if ((argc %26lt; 2) || (sscanf(argv[1],"%d",%26amp;n) != 1))


{


cout %26lt;%26lt; "usage : " %26lt;%26lt; argv[0] %26lt;%26lt; " n" %26lt;%26lt; endl;


return -1;


}


if (n %26lt; 0) // inverted


{


n *= -1;


startX = n-1;


endX = increment = -1;


}


else // normal


{


startX = 0;


endX = n;


increment = 1;


}


for (int i = startX; i != endX; i += increment)


{


cout %26lt;%26lt; setw(n-i) %26lt;%26lt; star;


for (int j = 1; j %26lt; (i*2)+1; j++) cout %26lt;%26lt; star;


cout %26lt;%26lt; endl;


}


return 0;


}
Reply:Basically, you need to swap the for loop that prints the spaces with the for loop that prints the *.





#include%26lt;iostream.h%26gt;


#include%26lt;conio.h%26gt;


int main()


{


clrscr();


int i,j,k,l=1,num;


cout%26lt;%26lt;"Enter the no:"%26lt;%26lt;endl;


cin%26gt;%26gt;num;


for(k=num; k%26gt;=1; k--)


{


for(j=1; j%26lt;=l; j++)


{


cout%26lt;%26lt;" ";


}


if( l %26lt;= num)


{


for(i=k; i%26gt;=1; i--)


cout %26lt;%26lt; "*" %26lt;%26lt; " ";


}


l++;


cout%26lt;%26lt;endl;


}


getch();


return 0;





}